Can you win an endgame with symmetrical pawns and one rook for each player?

Something I'm confused about. In the Endgame practice section under drills, there is a rook endgame you can practice called "Rook Endgame: Symmetrical Pawns". With the way the pieces are set up in this endgame (the g and h pawns on their original squares for both sides and the kings behind the respective g pawns) is a win possible assuming both sides play the best moves?

No.

I'm really struggling with this one too, not sure what's required for this drill or how to achieve anything except a draw

I would also like any tips about this one.

     Unless there is something about the rook positions that would let one of them get trapped and/or shut out of the play, Capablanca himself couldn't win that game. Even 3 pawns vs 2 is theoretically drawn,, and 4 vs 3, all  on one side of the board is a draw most of the time.

It's obviously possible. e.g.

You need to give the position of the rooks.

I think winning positions are limited to those where the side to move can immediately take the unprotected opponent's rook without leaving his own rook en prise or move his rook to the opponent's first rank on the a-e files with the opponents rook adjacent to the king on the h file.

All rook endings are draws, but the better player usually wins them.

yes you can

it depends if you use your pawns right and probe for weaknesses, but with best play it's almost always a draw unless the king is taking a vacation or something

Lomonosov shows draw with best play.

If you're talking about the previous position that's probably because Lomonosov only goes up to 7 men.