Way to search members by rating?

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KnightNotHorse

Hi -- was just curious if there was a way to browse members by ranking.  I am a beginner and was just wondering how many others out there have a ranking between 1000 - 1100 (for example).  Thanks!

erik
go to chess > players and use the search bar to put in your rating range...
MM78

I have a follow on question, you have country lists set up which you can view by latest log on, alphabetical etc.  It would be great if you could sort by rating also, I'd like to play against other people from home but you basically have to go into each and every profile to see level and indeed if they are active or not in playing terms. (Well done to one guy who only seems to play women) Alternatively if it gave the country in the overall players list that would work. 

 

Great site, I will be signing up for premium next month when I clear my Christmas creit cards bills :-)

KnightNotHorse
Thank you!  I also really like how you can sort by # of games -- at first, I wasn't sure why this option was available, but if you are looking for a solid player in a certain range, by seeing the number of games he/she has played, you know how close to the listed rating they really are (e.g. someone who is amazing with a 1200 rating because he/she just joined on vs. someone with a 1200 rating who has played 500 games).  Excellent!
KungPowKing

Is this still how to search for players of any rating/# of games. I can't seem to figure this out.

danstorm_00

Yes. Just simply go to https://www.chess.com/members

Then on your right you need to select Advanced, then Rapid/Blitz/Bullet and then your desired range:

pumpkin_LN
danstorm_00 wrote:

Yes. Just simply go to https://www.chess.com/members

Then on your right you need to select Advanced, then Rapid/Blitz/Bullet and then your desired range:

this doesn't seem to work for very small ranges - I tried searching up a player with blitz rating 1000 to 1010 and the top result had a rating of 1034. seems fine for rapid chess but I haven't experimented that much.

Rudrapriyo-Bose

Its very tricky question. Can anyone plz tell me