What is The Square Root of "Infinity i?"

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One_Zeroth

It is, for the first time!!!

e^(0.25 *pi i+infinity)

davishii

Chat GPT is your friend

One_Zeroth

Theoretical Novelty in Math.

One_Zeroth

Bump.

Doomed_Noob

The square root of infinity is infinity

Whatever operation you use on infinity whether it's + - * / will be infinity. Even infinity divided by infinity is infinity. You don't treat infinity like a number you treat it like a concept. Infinity can fit inside infinity an infinite number of times.

However there are lesser and greater infinities. Infinity -1 is smaller than infinity. This is because while infinity is not a number, it is countable. In fact you could count to infinity your entire life. You wouldn't ever stop but you could do it.

x6px

Megaphone - you have so much to say!

Doomed_Noob

Infinity is considered accessible because it is countable. There are also inaccessible numbers which cannot be accessed by counting.

That conceptual jump you make to go from finite numbers to infinity is smaller than the conceptual jump needed to go from infinity to inaccessible numbers. They are so vast and monolithic that they cannot be reached from the finite.

This one is boring to start with, but is a great watch starting around 18:00

One_Zeroth

You're totally wasting my time, "Doomed Noob."

Only your first sentence is correct.

I will refute your post, later

One_Zeroth

"The square root of infinity is infinity."

Correct. It is the Principle 3rd, 4th and nth root of infinity where n is a natural number.

"Whatever operation you use on infinity whether it's + - * / will be infinity."

Nope, -infinity is not infinity.

How can you post such inanities

"Even infinity divided by infinity is infinity."

Or any positive number.

"You don't treat infinity like a number you treat it like a concept. Infinity can fit inside infinity an infinite number of times."

Well then you are treating it as a number. You are just not making sense.

"However there are lesser and greater infinities. Infinity -1 is smaller than infinity."

Nope it is just infinity. Not a number, though.

"This is because while infinity is not a number, it is countable. In fact you could count to infinity your entire life. You wouldn't ever stop but you could do it."

??? No you couldn't 👎

One_Zeroth
Doomed_Noob wrote:

Infinity is considered accessible because it is countable. There are also inaccessible numbers which cannot be accessed by counting.

That conceptual jump you make to go from finite numbers to infinity is smaller than the conceptual jump needed to go from infinity to inaccessible numbers. They are so vast and monolithic that they cannot be reached from the finite.

This one is boring to start with, but is a great watch starting around 18:00

Please GO AWAY

nickmyakovsky

Negative infinity doesn't have a square root! Everyone knows that!!

One_Zeroth
nickmyakovsky wrote:

Negative infinity doesn't have a square root! Everyone knows that!!

Yes it does. It's infinity i.

IntellectuallySound

In mathematics, infinity is not a number, but rather a concept that represents an unbounded quantity. Therefore, it is not possible to take the square root of infinity

IntellectuallySound

but then again the value of e^(0.5*pi i+infinity) is undefined. However, if you are asking whether e^(0.5*pi i+infinity) is equal to infinity, the answer would have to be yes

One_Zeroth
IntellectuallySound wrote:

In mathematics, infinity is not a number, but rather a concept that represents an unbounded quantity. Therefore, it is not possible to take the square root of infinity

Because infinity*infinity is infinity, the square root of infinity is infinity.

YOU LIED!

One_Zeroth
IntellectuallySound wrote:

but then again the value of e^(0.5*pi i+infinity) is undefined. However, if you are asking whether e^(0.5*pi i+infinity) is equal to infinity, the answer would have to be yes

Nope it is square root of infinity i !

One_Zeroth

Oops, it is e^(.0.25 pi+infinity)

One_Zeroth
One_Zeroth wrote:

It is, for the first time!!!

e^(0.25 *pi i+infinity)

Updated

One_Zeroth

(e^0.25 pi i+infinity)*(e^025 pi i) is infinity i!

As stated as said.

One_Zeroth

COOL