Can I force a swiss torunament to have at least a "specific number" of rounds?

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dragaopandinha

Hello!

We have a club with small amount of players. ( around 8 can join for each tournament ). As we experienced when we start a swiss system based tounament the system always determines the tournaments rounds as players/2 -1. So when we set the tournament to be 5 rounds but we have only 7 players , it creates a 3 rounds tournament, what is not enough for us. Is there any way to force the system to create a 5 rounds swiss tournament in this case? ( It could set a player bye if it could not pair - the player from the bottom who has not been bye in the earlier rounds for example . This could be a nice feature for such a tourney can have small amount of participants). Thank you for your help in advance!

notmtwain

Are you sure that's the formula? For 30 players, 14 rounds? For 100 players, 49 rounds?

notmtwain

The point of a Swiss system tournament is to allow the chance to produce a clear winner as quickly as possible without eliminating anyone.

https://www.chess.com/forum/view/chess-organizers/number-of-rounds-in-swiss

Says for n players, you need x rounds where 2^x>= n to have the chance for a clear winner. For 7 players, 3 rounds works. (2^3=8) For 9-16 players, 4 rounds works.

Yes, if everyone draws all games, you don't get a winner but that doesn't happen very often.

I don't play in clubs but it would be unlike chess.com to allow free control of the number of rounds. 

Can you play a round robin, where everyone plays once ( or twice) against everyone?

dragaopandinha
notmtwain wrote:

Are you sure that's the formula? For 30 players, 14 rounds? For 100 players, 49 rounds?

Hello! No sorry if we have even number of player it is players / 2 , and I am not sure , but when we had 8 player we had 4 rounds, when we had 7 it was 3 rounds.

dragaopandinha
notmtwain wrote:

The point of a Swiss system tournament is to allow the chance to produce a clear winner as quickly as possible without eliminating anyone.

https://www.chess.com/forum/view/chess-organizers/number-of-rounds-in-swiss

Says for n players, you need x rounds where 2^x>= n to have the chance for a clear winner. For 7 players, 3 rounds works. (2^3=8) For 9-16 players, 4 rounds works.

Yes, if everyone draws all games, you don't get a winner but that doesn't happen very often.

I don't play in clubs but it would be unlike chess.com to allow free control of the number of rounds. 

Can you play a round robin, where everyone plays once ( or twice) against everyone?

No round robin would be too much . 7 rounds it would need in case of 8 players at least. We want only fix number of rounds because our time is limited , but we dont really know how many players we will have.  There are some chess organizer programs which can solve this problem and just create "bye" player from the bottom ( based on the actual tournament scores ) after each rounds if it can not give a pair for anyone. I dont know why chess com organizer has this limitation if the tournament round number is set hogher ( 5 for example in our case ) 

dragaopandinha

Anyway Thank you notmtwain  for replying!

Martin_Stahl

If you are talking about the Live swiss tourneys here, no. The max rounds are based on the the number of players. I believe you need at least 10 for 5 rounds and I'm not sure they will run with less than 6 and 3 rounds.

zyzniewski

What software do you use? In theory, it should be possible but please remember the Swiss algorithm is very sophisticated, it tries to find the best pairs without violating it's rules (players in same score bracket, color preferences, etc). If you are lucky enough you might play a 5 rounds long tournament with 7 players but it's very likely algorithm won't pair later rounds.